Home › Forums › General Discussion › Aspirin c9h8o4 is prepared by reacting salicylic acid c7h6o3 with acetic anhydride c4h6o3
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October 1, 2018 at 8:40 am #52914
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02/08/2010 · C7H6O3 + C4H6O3= C9H8O4 + HC2H3O2 What mass of acetic anhydride is needed to completely consume 1.50 102 g salicylic acid? What is the maximum mass of …So let’s find out the number of moles of salicylic acid there is in 100g. Mr salicylic acid = 138 g mol-1 because: It has 7 Carbon atoms at 12g mol-1 and 6 Hydrogen atoms at 1g mol-1 and 3 Oxygen atoms at 16g mol-1. 712 + 61 + 3*16 = 138g mol-1. m/Mr = 100/138 = 0.7246…mol of salicylic acid. There will also be 0.7246… mol of aspirin. The Mr of aspirin is 180g mol-1.11/06/2009 · Aspirin (acetylsalicylic acid, C9H8O4) can be prepared by reacting salicylic acid (C7H6O3) with acetic anhydride (C4H6O3) according to the following …Answer to Aspirin is prepared by reaction of salicylic acid (C7H6O3) with acetic anhydride (C4H6O3) according to the following….10/07/2008 · Aspirin (C9H8O4) is synthesized by reacting salicylic acid (C7H6O3) with acetic anhydride (C4H6O3). The balanced equation is given below. C7H6O3 + C4H6O3 …15/07/2010 · Aspirin (C9H8O4) is synthesized by reacting salicylic acid (C7H6O3) with acetic anhydride (C4H6O3). The balanced equation is given below. C7H6O3 + C4H6O3 …10/08/2008 · Best Answer: C7H6O3 + C4H6O3 —-> C9H8O4 + HC2H3O2 1 mol salicylic acid (C7H6O3) reacts with 1 mol of acetic anhydride (C4H6O3) to make 1 mol of aspirin …chemistry Asprin, C9H8O4, is prepared by reacting salicylic acid, C7H6O3, with acetic anhydride, C4H6O3, in the reaction C7H6O3(s) + C4H6O3(l) -> C9H8O4(s) + C2H4O2(l …Answer to Aspirin, C9H8O4, Synthesized by reacting salicylic acid, C7H6O3, with acetic anhydride, C4H6O3: 2C7H6O3(s) + C4H6O3(l) …Aspirin (C9H8O4) is synthesized by the reaction of salicylic acid (C7H6O3) with acetic anhydride, C4H6O3. 2C7H6O3 + C4H6O3 −→ 2C9H8O4 + H2O When 19 g of C7H6O3 and 19 g of C4H6O3 react, which is the limiting reagent? chemistry A student prepared aspirin (C9H8O4) in a laboratory experiment using the following reaction. -
June 18, 2019 at 8:19 am #138041
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